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AMC 10AMC 12

Prime Powers and Divisor Structure

40 minutes of active learning · Difficulty 4/10 · Lesson

Prime factorization turns a large integer into a small collection of exponent choices. Those choices reveal its divisors, perfect powers, and hidden factors inside products.

What you will learn

  • Analyze prime exponents
  • Count divisors
  • Apply factor constraints

Keep paper and a pencil nearby. Try each problem before opening a hint, and mark sections reviewed as you work through them.

A divisor is a choice of exponents

Every positive integer greater than one has a unique factorization into primes, apart from the order of the factors. If an integer contains pap^a, a divisor may contain pp to any exponent from zero through aa. Choosing exponent zero means leaving that prime out. Choices for different primes are independent, so multiplication counts the complete set of positive divisors.

For N=paqbN=p^a q^b with different primes, the divisor count is (a+1)(b+1)(a+1)(b+1). The added ones include zero exponents, not an extra prime factor. To impose a condition such as divisibility by a given number, restrict the allowed exponents first and only then multiply the counts.

Perfect powers and shared factors

A positive integer is a square exactly when every prime exponent is even. A cube requires every exponent to be divisible by three. Thus counting square divisors means counting even exponent options at each prime. To make an integer a square by multiplying, supply precisely the primes whose exponents are odd; adding unnecessary factors makes the multiplier larger.

The greatest common divisor of two integers takes the smaller exponent at each prime, because a shared divisor cannot exceed either supply. The least common multiple takes the larger exponent, because it must contain both supplies. These descriptions explain the formulas and prevent confusing a shared factor with a common multiple.

Count prime contributions in a factorial

A factorial multiplies all positive integers up to its input. To count factors of a prime pp, first count the multiples of pp. Each contributes at least one copy. Multiples of p2p^2 contribute an additional copy, multiples of p3p^3 another, and so on. Add these nested counts rather than counting each multiple only once.

Trailing decimal zeros come from factors of ten, each requiring a pair consisting of a two and a five. In a factorial there are at least as many twos as fives, so fives are the limiting supply. In a general product you must compare both counts instead of automatically counting fives.

See the reasoning unfold

Pause after each step and predict what comes next.

Worked example 1

Count without listing

How many positive divisors does 23⋅32⋅52^3\cdot3^2\cdot5 have?

  1. The exponent of 2 has 4 choices, from 0 through 3.

1 of 3 steps revealed

Worked example 2

Select only square divisors

How many positive square divisors does 25⋅34⋅72^5\cdot3^4\cdot7 have?

  1. An even exponent of 2 can be 0, 2, or 4.

1 of 3 steps revealed

Worked example 3

Find a prime inside a factorial

What is the exponent of 3 in the prime factorization of 40!40!?

  1. There are ⌊40/3⌋=13\lfloor40/3\rfloor=13 multiples of 3.

1 of 3 steps revealed

Common mistakes to catch

  • Omitting zero from the list of allowed prime exponents.
  • Counting each multiple of a prime only once inside a factorial.
  • Using maximum rather than minimum exponents for a GCD.

Try with support

Guided practice

Choose a strategy, take a first step, and use the hints when you need direction.

Guided problem 1

Difficulty 4/10

How many positive divisors does 24⋅522^4\cdot5^2 have?

For example: 12, 0.75, or 3/4.

Guided problem 2

Difficulty 4/10

Find gcd⁡(23⋅3⋅52,22⋅33⋅5)\gcd(2^3\cdot3\cdot5^2,2^2\cdot3^3\cdot5).

For example: 12, 0.75, or 3/4.

Put it into practice

Independent practice

Work on your own first. If you reveal a solution, work through it and mark it reviewed.

Independent problem 1

Difficulty 5/10

How many positive divisors of 25⋅32⋅52^5\cdot3^2\cdot5 are multiples of 12?

For example: 12, 0.75, or 3/4.

Independent problem 2

Difficulty 5/10

Find the least positive integer kk for which 756k756k is a perfect square.

For example: 12, 0.75, or 3/4.

Independent problem 3

Difficulty 5/10

How many trailing decimal zeros does 28!28! have?

For example: 12, 0.75, or 3/4.

Independent problem 4

Difficulty 5/10

Find the smallest positive multiple of 10 with exactly six positive divisors.

For example: 12, 0.75, or 3/4.

Bring it together

  • Prime exponents encode divisibility.
  • Restrict exponent choices to count special divisors.
  • Add all prime-power layers when analyzing a factorial.

Finish with understanding.

Review each section and example, then solve each problem or work through its solution.

  • 0 / 6 sections reviewed
  • 0 / 3 worked examples explored
  • 0 / 6 problems solved or reviewed

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