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AMC 10AMC 12

Quadratics, Discriminants, and Intersections

40 minutes of active learning · Difficulty 4/10 · Lesson

You do not always need to calculate roots to understand a quadratic. Its square form, discriminant, and graph describe the same relationship from three useful viewpoints.

What you will learn

  • Connect quadratic forms
  • Classify real roots
  • Model intersections

Keep paper and a pencil nearby. Try each problem before opening a hint, and mark sections reviewed as you work through them.

Square form locates the turning point

A quadratic with nonzero leading coefficient can be written as a(x−h)2+ka(x-h)^2+k. Because the square is smallest at x=hx=h, this form identifies the vertex (h,k)(h,k). Positive aa makes the graph open upward and gives a minimum; negative aa makes it open downward and gives a maximum. The sign of the leading coefficient therefore affects the meaning of every bound.

The horizontal axis corresponds to output zero. A quadratic graph may cross it twice, touch it once, or miss it. Compare the vertex height and opening direction before doing algebra. This geometric prediction is a useful independent check on the number of roots produced by a calculation.

The discriminant counts real roots

The quadratic formula solves ax2+bx+c=0ax^2+bx+c=0 as x=(−b±b2−4ac)/(2a)x=(-b\pm\sqrt{b^2-4ac})/(2a). The quantity D=b2−4acD=b^2-4ac is the discriminant. If D>0D>0, the two signs produce distinct real roots. If D=0D=0, they produce the same root. If D<0D<0, no real square root exists and there are no real roots.

A double root is still one distinct input, even though its factor occurs twice. When a question says exactly one intersection, translate it into D=0D=0 for the resulting quadratic. If a parameter changes the leading coefficient, first check separately whether it can become zero, because the equation would then cease to be quadratic.

An intersection satisfies both rules

Two graphs intersect where the same input produces the same output. Set their formulas equal, move everything to one side, and solve the resulting equation. Each permitted input then determines an output. Counting algebraic roots counts intersection points only after checking domains and ensuring no denominator clearing created an invalid root.

A tangent line meets a parabola at a double intersection input. Horizontal tangents occur at the vertex, while other tangent lines can be studied using a discriminant equation. After determining a parameter, substitute it back to locate the contact point. This final step confirms both the algebraic condition and the geometric interpretation.

See the reasoning unfold

Pause after each step and predict what comes next.

Worked example 1

See a missing intersection two ways

How many real roots does x2−8x+18=0x^2-8x+18=0 have?

  1. Complete the square: x2−8x+18=(x−4)2+2x^2-8x+18=(x-4)^2+2.

1 of 3 steps revealed

Worked example 2

Intersect a line and a parabola

The graphs y=x2+1y=x^2+1 and y=4x−2y=4x-2 intersect. Find the sum of their intersection x-coordinates.

  1. Set outputs equal: x2+1=4x−2x^2+1=4x-2.

1 of 3 steps revealed

Worked example 3

Find a parameter for a double positive root

For which positive kk does x2−kx+16=0x^2-kx+16=0 have exactly one real root?

  1. The discriminant must be zero: k2−64=0k^2-64=0.

1 of 3 steps revealed

Common mistakes to catch

  • Counting a repeated root as two distinct intersection points.
  • Using the discriminant formula after the leading coefficient becomes zero.
  • Forgetting to apply a stated sign restriction to a parameter.

Try with support

Guided practice

Choose a strategy, take a first step, and use the hints when you need direction.

Guided problem 1

Difficulty 4/10

How many distinct real roots does 2x2+4x+5=02x^2+4x+5=0 have?

For example: 12, 0.75, or 3/4.

Guided problem 2

Difficulty 4/10

The horizontal line y=cy=c is tangent to y=x2−2x+5y=x^2-2x+5. Find cc.

For example: 12, 0.75, or 3/4.

Put it into practice

Independent practice

Work on your own first. If you reveal a solution, work through it and mark it reviewed.

Independent problem 1

Difficulty 5/10

The discriminant of x2+bx+12x^2+bx+12 is 25. Find b2b^2.

For example: 12, 0.75, or 3/4.

Independent problem 2

Difficulty 5/10

The line y=mxy=mx meets y=x2+9y=x^2+9 at exactly one point. Find m2m^2.

For example: 12, 0.75, or 3/4.

Independent problem 3

Difficulty 5/10

Find the larger real solution of (x−4)2=9(x-4)^2=9.

For example: 12, 0.75, or 3/4.

Independent problem 4

Difficulty 5/10

For some real tt, the equation x2−2tx+t+2=0x^2-2tx+t+2=0 has root 1. Find its other root.

For example: 12, 0.75, or 3/4.

Bring it together

  • Square form locates the vertex.
  • The discriminant counts distinct real roots.
  • Set outputs equal to translate a graph intersection into algebra.

Finish with understanding.

Review each section and example, then solve each problem or work through its solution.

  • 0 / 6 sections reviewed
  • 0 / 3 worked examples explored
  • 0 / 6 problems solved or reviewed

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