Skip to main content
STREAK 0dLV 1 0 XP
Institute site
AMC 10AMC 12

Bounds and Extrema

40 minutes of active learning · Difficulty 4/10 · Lesson

A competition problem may ask for the largest possible area or the smallest possible expression. You can often answer by proving a bound and showing exactly when it is reached.

What you will learn

  • Derive useful inequalities
  • Locate equality cases
  • Optimize elementary expressions

Keep paper and a pencil nearby. Try each problem before opening a hint, and mark sections reviewed as you work through them.

Start with something that cannot be negative

For every real tt, its square is nonnegative. This elementary fact supplies many useful bounds. If you rewrite an expression as a constant plus a square, the constant is a lower bound. If you rewrite it as a constant minus a square, the constant is an upper bound. Equality occurs only when the square is zero.

Completing the square organizes a quadratic into this form. Take half the linear coefficient inside the square, then compensate for the constant you introduced. With a leading coefficient other than one, factor it from the quadratic and linear terms first. Expand your final expression as a quick check that the rewriting is exact.

Balanced quantities control products

For real a,ba,b, the identity (a−b)2=(a+b)2−4ab(a-b)^2=(a+b)^2-4ab shows that 4ab≤(a+b)24ab\le(a+b)^2. When the sum is fixed, this limits the product, and equality requires a=ba=b. Geometrically, among rectangles with a fixed perimeter, the square has the greatest area. The conclusion follows from algebra rather than from how a sketch looks.

For positive quantities, the same reasoning gives the arithmetic-geometric mean inequality. Be attentive to the permitted domain: if lengths must be integers or one variable must lie in a certain interval, the balanced equality case may be unavailable. Then compare the nearest allowed candidates or analyze how far the expression lies from the ideal value.

Prove attainability, not just an estimate

A minimum is an allowed value that is no larger than any other allowed value. Merely proving an expression is at least some number does not show that number is the minimum; you must exhibit an input that attains it. This is particularly important for strict inequalities and domains that omit an endpoint.

Reciprocal expressions reward a similar structural approach. For x>0x>0 and k>0k>0, compare x+k/xx+k/x by observing that (x−k/x)2≥0(\sqrt{x}-\sqrt{k/x})^2\ge0. This gives a lower bound and an equality condition simultaneously. In a contest solution, state the sign assumption, derive the bound, and check whether the equality input is permitted before announcing the result.

See the reasoning unfold

Pause after each step and predict what comes next.

Worked example 1

Find a minimum by completing the square

Find the minimum value of x2−10x+31x^2-10x+31 over real xx.

  1. Complete the square: x2−10x+31=(x−5)2+6x^2-10x+31=(x-5)^2+6.

1 of 3 steps revealed

Worked example 2

A rectangle with fixed boundary length

A rectangle has perimeter 28. What is its maximum possible area?

  1. If side lengths are a,b>0a,b>0, then a+b=14a+b=14.

1 of 3 steps revealed

Worked example 3

A reciprocal pair

For t>0t>0, find the minimum of t+16/tt+16/t.

  1. The nonnegative square (t−4/t)2(\sqrt t-4/\sqrt t)^2 expands to t+16/t−8t+16/t-8.

1 of 3 steps revealed

Common mistakes to catch

  • Announcing a bound without showing it can be attained.
  • Applying a positive-variable inequality to a negative variable.
  • Ignoring integer or interval restrictions on the equality case.

Try with support

Guided practice

Choose a strategy, take a first step, and use the hints when you need direction.

Guided problem 1

Difficulty 4/10

Find the minimum of 2x2+12x+252x^2+12x+25 over real xx.

For example: 12, 0.75, or 3/4.

Guided problem 2

Difficulty 4/10

Positive numbers a,ba,b have sum 18. Find the maximum of abab.

For example: 12, 0.75, or 3/4.

Put it into practice

Independent practice

Work on your own first. If you reveal a solution, work through it and mark it reviewed.

Independent problem 1

Difficulty 5/10

Find the maximum of 11−3(x−2)211-3(x-2)^2 over real xx.

For example: 12, 0.75, or 3/4.

Independent problem 2

Difficulty 5/10

Positive integers a,ba,b satisfy a+b=15a+b=15. Find the maximum product abab.

For example: 12, 0.75, or 3/4.

Independent problem 3

Difficulty 5/10

For x>0x>0, find the minimum of 3x+12/x3x+12/x.

For example: 12, 0.75, or 3/4.

Independent problem 4

Difficulty 5/10

For 0≤x≤20\le x\le2, find the minimum of (x−5)2+1(x-5)^2+1.

For example: 12, 0.75, or 3/4.

Bring it together

  • Rewrite a target using a nonnegative square.
  • Identify the equality condition in the same calculation.
  • Check that the equality input belongs to the allowed domain.

Finish with understanding.

Review each section and example, then solve each problem or work through its solution.

  • 0 / 6 sections reviewed
  • 0 / 3 worked examples explored
  • 0 / 6 problems solved or reviewed

Loading your saved progress…

Your answers, revealed steps, and lesson progress are saved in this browser.